Algebra Questionnaire

MATH 20TEST 3
Write your number in the box above.
Due:
Tuesday, 7-28-2020, 11:59 p.m.
Name
(Show necessary work.)
(1)
Let
P (x) = 2×2 − 3x + 7;
(a)
Find P (−5)
(1a)
(b)
Find P (3a − 2)
(1b)
2x(2×2 − x − 5) − 3x(7×2 − 3x − 2) =
(2)
Simplifying:
(3)
Multiply:
(4)
Expanding and simplifying:
(4×2 − 5x + 1)(3×2 − 2x − 4) =
(x + 5y)2 − (5x − 3y)2 =
(2)
(3)
(4)
(5)
Factor:
3×5 − 48x =
(5)
(6)
Factor:
5×3 − 20×2 − 105x =
(6)
(7)
Factor:
4×3 − x2 − 36x + 9 =
(7)
(8)
Factor:
27×3 − 64y 3 =
(8)
(9)
Solve for x:
2x(x − 7)(4x + 5)(5x − 8) = 0
(9)
(10)
6×2 + 5x − 4 = 0
Solve for x:
Rewriting:
p
(a) write 7 5×2 y 5 in power notation.
(10)
(11)
3
(b) write (8x) 4 in radical notation.
2
(12)
Simplifying:
(27a12 b15 ) 3 =
(13)
Simplifying:
( 36
)− 2 =
49
(14)
Simplifying:
(15)
Expanding:
1
√
4
(11b)
(12)
(13)
32a31 b18 c4 =
1
(11a)
1
(2x 2 − 5y 2 )2 =
(14)
(15)
√
√
√
7 4 81 − 3 3 64 + 5 3 27 =
(16)
Simplifying:
(17)
Rationalizing the denominator:
(18)
Solve:
(19)
Find the following powers:
√
√ 6√
5+ 2
(16)
=
(17)
8−x=x−2
(18)
(a) i310 =
(19a)
(b) (i12 )2 · i87 =
(19b)
(20)
(a)
Rewrite the following imaginary numbers, using i:
√
−49 =
(b)
√
−180 =
(21)
(−11 + 7i) − (−5i + 4) + (9 − 15i) =
(21)
(22)
2i(5 + 3i)(7 − 9i) =
(22)
(23)
(9 − 5i)2 =
(23)
(24)
3+2i
4−3i
(24)
(25)
2
( i−2
3+i ) =
=
(25)
Math20
Test 3,
100 points
MATH 20
TEST 3
Write your number in the box above.
Due:
Tuesday, 7-28-2020, 11:59 p.m.
Name
(Show necessary work.)
(1)
Let
P (x) = 2×2 − 3x + 7;
(a)
Find P (−5)
(1a)
(b)
Find P (3a − 2)
(1b)
2x(2×2 − x − 5) − 3x(7×2 − 3x − 2) =
(2)
Simplifying:
(3)
Multiply:
(4)
Expanding and simplifying:
(4×2 − 5x + 1)(3×2 − 2x − 4) =
(x + 5y)2 − (5x − 3y)2 =
(2)
(3)
(4)
(5)
Factor:
3×5 − 48x =
(5)
(6)
Factor:
5×3 − 20×2 − 105x =
(6)
(7)
Factor:
4×3 − x2 − 36x + 9 =
(7)
(8)
Factor:
27×3 − 64y 3 =
(8)
(9)
Solve for x:
2x(x − 7)(4x + 5)(5x − 8) = 0
(9)
(10)
6×2 + 5x − 4 = 0
Solve for x:
Rewriting:
p
(a) write 7 5×2 y 5 in power notation.
(10)
(11)
3
(b) write (8x) 4 in radical notation.
2
(12)
Simplifying:
(27a12 b15 ) 3 =
(13)
Simplifying:
( 36
)− 2 =
49
(14)
Simplifying:
(15)
Expanding:
1
√
4
(11b)
(12)
(13)
32a31 b18 c4 =
1
(11a)
1
(2x 2 − 5y 2 )2 =
(14)
(15)
√
√
√
7 4 81 − 3 3 64 + 5 3 27 =
(16)
Simplifying:
(17)
Rationalizing the denominator:
(18)
Solve:
(19)
Find the following powers:
√
√ 6√
5+ 2
(16)
=
(17)
8−x=x−2
(18)
(a) i310 =
(19a)
(b) (i12 )2 · i87 =
(19b)
(20)
(a)
Rewrite the following imaginary numbers, using i:
√
−49 =
(b)
√
−180 =
(21)
(−11 + 7i) − (−5i + 4) + (9 − 15i) =
(21)
(22)
2i(5 + 3i)(7 − 9i) =
(22)
(23)
(9 − 5i)2 =
(23)
(24)
3+2i
4−3i
(24)
(25)
2
( i−2
3+i ) =
=
(25)
Math20
Test 3,
100 points
MATH 20
TEST 3
Write your number in the box above.
Due:
Tuesday, 7-28-2020, 11:59 p.m.
Name
(Show necessary work.)
(1)
Let
P (x) = 2×2 − 3x + 7;
(a)
Find P (−5)
(1a)
(b)
Find P (3a − 2)
(1b)
2x(2×2 − x − 5) − 3x(7×2 − 3x − 2) =
(2)
Simplifying:
(3)
Multiply:
(4)
Expanding and simplifying:
(4×2 − 5x + 1)(3×2 − 2x − 4) =
(x + 5y)2 − (5x − 3y)2 =
(2)
(3)
(4)
(5)
Factor:
3×5 − 48x =
(5)
(6)
Factor:
5×3 − 20×2 − 105x =
(6)
(7)
Factor:
4×3 − x2 − 36x + 9 =
(7)
(8)
Factor:
27×3 − 64y 3 =
(8)
(9)
Solve for x:
2x(x − 7)(4x + 5)(5x − 8) = 0
(9)
(10)
6×2 + 5x − 4 = 0
Solve for x:
Rewriting:
p
(a) write 7 5×2 y 5 in power notation.
(10)
(11)
3
(b) write (8x) 4 in radical notation.
2
(12)
Simplifying:
(27a12 b15 ) 3 =
(13)
Simplifying:
( 36
)− 2 =
49
(14)
Simplifying:
(15)
Expanding:
1
√
4
(11b)
(12)
(13)
32a31 b18 c4 =
1
(11a)
1
(2x 2 − 5y 2 )2 =
(14)
(15)
√
√
√
7 4 81 − 3 3 64 + 5 3 27 =
(16)
Simplifying:
(17)
Rationalizing the denominator:
(18)
Solve:
(19)
Find the following powers:
√
√ 6√
5+ 2
(16)
=
(17)
8−x=x−2
(18)
(a) i310 =
(19a)
(b) (i12 )2 · i87 =
(19b)
(20)
(a)
Rewrite the following imaginary numbers, using i:
√
−49 =
(b)
√
−180 =
(21)
(−11 + 7i) − (−5i + 4) + (9 − 15i) =
(21)
(22)
2i(5 + 3i)(7 − 9i) =
(22)
(23)
(9 − 5i)2 =
(23)
(24)
3+2i
4−3i
(24)
(25)
2
( i−2
3+i ) =
=
(25)
Math20
Test 3,
100 points
MATH 20
TEST 3
Write your number in the box above.
Due:
Tuesday, 7-28-2020, 11:59 p.m.
Name
(Show necessary work.)
(1)
Let
P (x) = 2×2 − 3x + 7;
(a)
Find P (−5)
(1a)
(b)
Find P (3a − 2)
(1b)
2x(2×2 − x − 5) − 3x(7×2 − 3x − 2) =
(2)
Simplifying:
(3)
Multiply:
(4)
Expanding and simplifying:
(4×2 − 5x + 1)(3×2 − 2x − 4) =
(x + 5y)2 − (5x − 3y)2 =
(2)
(3)
(4)
(5)
Factor:
3×5 − 48x =
(5)
(6)
Factor:
5×3 − 20×2 − 105x =
(6)
(7)
Factor:
4×3 − x2 − 36x + 9 =
(7)
(8)
Factor:
27×3 − 64y 3 =
(8)
(9)
Solve for x:
2x(x − 7)(4x + 5)(5x − 8) = 0
(9)
(10)
6×2 + 5x − 4 = 0
Solve for x:
Rewriting:
p
(a) write 7 5×2 y 5 in power notation.
(10)
(11)
3
(b) write (8x) 4 in radical notation.
2
(12)
Simplifying:
(27a12 b15 ) 3 =
(13)
Simplifying:
( 36
)− 2 =
49
(14)
Simplifying:
(15)
Expanding:
1
√
4
(11b)
(12)
(13)
32a31 b18 c4 =
1
(11a)
1
(2x 2 − 5y 2 )2 =
(14)
(15)
√
√
√
7 4 81 − 3 3 64 + 5 3 27 =
(16)
Simplifying:
(17)
Rationalizing the denominator:
(18)
Solve:
(19)
Find the following powers:
√
√ 6√
5+ 2
(16)
=
(17)
8−x=x−2
(18)
(a) i310 =
(19a)
(b) (i12 )2 · i87 =
(19b)
(20)
(a)
Rewrite the following imaginary numbers, using i:
√
−49 =
(b)
√
−180 =
(21)
(−11 + 7i) − (−5i + 4) + (9 − 15i) =
(21)
(22)
2i(5 + 3i)(7 − 9i) =
(22)
(23)
(9 − 5i)2 =
(23)
(24)
3+2i
4−3i
(24)
(25)
2
( i−2
3+i ) =
=
(25)
Math20
Test 3,
100 points
MATH 20
TEST 3
Write your number in the box above.
Due:
Tuesday, 7-28-2020, 11:59 p.m.
Name
(Show necessary work.)
(1)
Let
P (x) = 2×2 − 3x + 7;
(a)
Find P (−5)
(1a)
(b)
Find P (3a − 2)
(1b)
2x(2×2 − x − 5) − 3x(7×2 − 3x − 2) =
(2)
Simplifying:
(3)
Multiply:
(4)
Expanding and simplifying:
(4×2 − 5x + 1)(3×2 − 2x − 4) =
(x + 5y)2 − (5x − 3y)2 =
(2)
(3)
(4)
(5)
Factor:
3×5 − 48x =
(5)
(6)
Factor:
5×3 − 20×2 − 105x =
(6)
(7)
Factor:
4×3 − x2 − 36x + 9 =
(7)
(8)
Factor:
27×3 − 64y 3 =
(8)
(9)
Solve for x:
2x(x − 7)(4x + 5)(5x − 8) = 0
(9)
(10)
6×2 + 5x − 4 = 0
Solve for x:
Rewriting:
p
(a) write 7 5×2 y 5 in power notation.
(10)
(11)
3
(b) write (8x) 4 in radical notation.
2
(12)
Simplifying:
(27a12 b15 ) 3 =
(13)
Simplifying:
( 36
)− 2 =
49
(14)
Simplifying:
(15)
Expanding:
1
√
4
(11b)
(12)
(13)
32a31 b18 c4 =
1
(11a)
1
(2x 2 − 5y 2 )2 =
(14)
(15)
√
√
√
7 4 81 − 3 3 64 + 5 3 27 =
(16)
Simplifying:
(17)
Rationalizing the denominator:
(18)
Solve:
(19)
Find the following powers:
√
√ 6√
5+ 2
(16)
=
(17)
8−x=x−2
(18)
(a) i310 =
(19a)
(b) (i12 )2 · i87 =
(19b)
(20)
(a)
Rewrite the following imaginary numbers, using i:
√
−49 =
(b)
√
−180 =
(21)
(−11 + 7i) − (−5i + 4) + (9 − 15i) =
(21)
(22)
2i(5 + 3i)(7 − 9i) =
(22)
(23)
(9 − 5i)2 =
(23)
(24)
3+2i
4−3i
(24)
(25)
2
( i−2
3+i ) =
=
(25)
Math20
Test 3,
100 points
MATH 20
TEST 3
Write your number in the box above.
Due:
Tuesday, 7-28-2020, 11:59 p.m.
Name
(Show necessary work.)
(1)
Let
P (x) = 2×2 − 3x + 7;
(a)
Find P (−5)
(1a)
(b)
Find P (3a − 2)
(1b)
2x(2×2 − x − 5) − 3x(7×2 − 3x − 2) =
(2)
Simplifying:
(3)
Multiply:
(4)
Expanding and simplifying:
(4×2 − 5x + 1)(3×2 − 2x − 4) =
(x + 5y)2 − (5x − 3y)2 =
(2)
(3)
(4)
(5)
Factor:
3×5 − 48x =
(5)
(6)
Factor:
5×3 − 20×2 − 105x =
(6)
(7)
Factor:
4×3 − x2 − 36x + 9 =
(7)
(8)
Factor:
27×3 − 64y 3 =
(8)
(9)
Solve for x:
2x(x − 7)(4x + 5)(5x − 8) = 0
(9)
(10)
6×2 + 5x − 4 = 0
Solve for x:
Rewriting:
p
(a) write 7 5×2 y 5 in power notation.
(10)
(11)
3
(b) write (8x) 4 in radical notation.
2
(12)
Simplifying:
(27a12 b15 ) 3 =
(13)
Simplifying:
( 36
)− 2 =
49
(14)
Simplifying:
(15)
Expanding:
1
√
4
(11b)
(12)
(13)
32a31 b18 c4 =
1
(11a)
1
(2x 2 − 5y 2 )2 =
(14)
(15)
√
√
√
7 4 81 − 3 3 64 + 5 3 27 =
(16)
Simplifying:
(17)
Rationalizing the denominator:
(18)
Solve:
(19)
Find the following powers:
√
√ 6√
5+ 2
(16)
=
(17)
8−x=x−2
(18)
(a) i310 =
(19a)
(b) (i12 )2 · i87 =
(19b)
(20)
(a)
Rewrite the following imaginary numbers, using i:
√
−49 =
(b)
√
−180 =
(21)
(−11 + 7i) − (−5i + 4) + (9 − 15i) =
(21)
(22)
2i(5 + 3i)(7 − 9i) =
(22)
(23)
(9 − 5i)2 =
(23)
(24)
3+2i
4−3i
(24)
(25)
2
( i−2
3+i ) =
=
(25)
Math20
Test 3,
100 points
MATH 20
TEST 3
Write your number in the box above.
Due:
Tuesday, 7-28-2020, 11:59 p.m.
Name
(Show necessary work.)
(1)
Let
P (x) = 2×2 − 3x + 7;
(a)
Find P (−5)
(1a)
(b)
Find P (3a − 2)
(1b)
2x(2×2 − x − 5) − 3x(7×2 − 3x − 2) =
(2)
Simplifying:
(3)
Multiply:
(4)
Expanding and simplifying:
(4×2 − 5x + 1)(3×2 − 2x − 4) =
(x + 5y)2 − (5x − 3y)2 =
(2)
(3)
(4)
(5)
Factor:
3×5 − 48x =
(5)
(6)
Factor:
5×3 − 20×2 − 105x =
(6)
(7)
Factor:
4×3 − x2 − 36x + 9 =
(7)
(8)
Factor:
27×3 − 64y 3 =
(8)
(9)
Solve for x:
2x(x − 7)(4x + 5)(5x − 8) = 0
(9)
(10)
6×2 + 5x − 4 = 0
Solve for x:
Rewriting:
p
(a) write 7 5×2 y 5 in power notation.
(10)
(11)
3
(b) write (8x) 4 in radical notation.
2
(12)
Simplifying:
(27a12 b15 ) 3 =
(13)
Simplifying:
( 36
)− 2 =
49
(14)
Simplifying:
(15)
Expanding:
1
√
4
(11b)
(12)
(13)
32a31 b18 c4 =
1
(11a)
1
(2x 2 − 5y 2 )2 =
(14)
(15)
√
√
√
7 4 81 − 3 3 64 + 5 3 27 =
(16)
Simplifying:
(17)
Rationalizing the denominator:
(18)
Solve:
(19)
Find the following powers:
√
√ 6√
5+ 2
(16)
=
(17)
8−x=x−2
(18)
(a) i310 =
(19a)
(b) (i12 )2 · i87 =
(19b)
(20)
(a)
Rewrite the following imaginary numbers, using i:
√
−49 =
(b)
√
−180 =
(21)
(−11 + 7i) − (−5i + 4) + (9 − 15i) =
(21)
(22)
2i(5 + 3i)(7 − 9i) =
(22)
(23)
(9 − 5i)2 =
(23)
(24)
3+2i
4−3i
(24)
(25)
2
( i−2
3+i ) =
=
(25)
Math20
Test 3,
100 points